# How do you find the vertex and the intercepts for #y=x^2+6x+5#?

##### 1 Answer

Aug 7, 2017

Here is what I would do:

#### Explanation:

When

**Vertex and #x# Intercepts**

**Note that** the following method will not work if the equation has no

Also note that there are other ways to find the vertex.

x^2+6x+5 = 0#

the

*Vertex*

The vertex is midway between the

The average is

To find the

The vertex is